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©1987 William J. Beaty

[SCHEMATIC OF DEVICE] (The earth-ground is not required.)

(The 1-Meg resistor is not required.)

This simple circuit can detect the invisible fields of voltage which surround all electrified objects. It acts as an electronic "electroscope."

Regular foil-leaf electroscopes deal with electrostatic potentials in the range of many hundreds or thousands of volts. The above device can detect one volt. Its sensitivity is ridiculously high. Since "static electricity" in our environment is actually a matter of high voltage, this device can sense those high-voltage electrically charged objects at a great distance. On a low-humidity day and with a 1/2 meter antenna wire, its little LED-light will respond strongly when someone combs their hair at a distance of five meters or more. If a metal object is lifted up upon a non-conductive support and touched against the sensor wire, the sensor can detect whether that object has an electrostatic potential of as little as one volt!

  • Note: I use the term "electrification" rather than "charging", in order to avoid confusion between electric charge and net-charge. "Charge" is the stuff on the negative electrons and positive protons, while "net-charge" is the imbalance between positive and negative particles which appears on everyday objects. Avoid saying that everyday objects become electrically "charged." After all, their atoms are always full of charges. Instead they become "electrified" whenever their pre-existing + and - charges are not equal.


  • 1 - Standard 9-volt battery
  • 1 - MPF102 Field Effect Transistor (FET) Radio Shack #276-2062, or mail order
  • 1 - any Red Light Emitting Diode (LED), eg Radio Shack #276-041
  • MISC:
    • Battery connector (#270-325)
    • Alligator Clip Leads (#278-1156)
    • solder, if desired
    • 1-meg resistor (not required)
    • plastic, fur, foil, comb, tape dispenser, plastic cup
[Drawing: FET and LED soldered to 9v connector]
(Tiny version bult atop a 9v battery connector)


Recommended book: Electrostatics by A. D. Moore (lots of projects) , also others



Warning: don't connect the battery until you are SURE you've hooked everything up exactly right. It's possible to burn out the FET or the LED if they are connected incorrectly. Don't let the transistor's wires bump together even briefly, or it will flash the LED and burn it out.

NOTE: Don't ever connect any LED directly to a 9-volt battery, it will burn out the LED. Without the transistor to limit the current, a bare LED needs a 1000-ohm resistor wired in series if connected to the 9-volt battery.

Warning: Avoid touching the Gate wire of the FET. Any small sparks jumping from your finger to the Gate wire can damage the transistor internally.

Use three clipleads. Bend the Gate wire of the FET upwards (see the small diagram above to see which lead is the Gate, or check the diagram on the cardboard of the Radio Shack FET.) The Gate acts as an antenna, so leave it unconnected. Use one cliplead to connect the middle transistor lead to the red positive lead for the 9V battery clip. Connect the remaining transistor lead to the positive lead of the LED (the longer LED lead is usually the positive one.) Connect the LED's remaining lead (the negative one) to the black negative lead for the 9V battery clip. Check all connections twice, then carefully connect the 9V battery to the battery clip. The LED should light up. If the LED remains dark, try lighting it up by waving an electrified plastic pen or ruler near the Gate wire (electrify the plastic by rubbing it on hair.)

The 1-meg resistor helps protect the FET from being harmed by any accidental sparks to its Gate lead. The circuit will work fine without this resistor. Just don't intentionally "zap" the Gate wire with an electrified object or finger.

To test the circuit, electrify a pen or a comb on your hair, then wave it close to the little "antenna" wire. The LED should go dark. When you remove the electrified pen or comb, the LED should light up again.

IF IT DOESN'T WORK, the humidity might be too high. Or, your LED might be wired backwards, or the transistor is connected wrong, or maybe your transistor is burned out. Make sure that the transistor is connected similar to the little drawing above. Also, if the polarity of the LED is reversed, the LED will not light up. Try changing the connections to your LED to reverse their order, then connect the battery and test the circuit again. If you suspect that humidity is very high, test this by rubbing a balloon or a plastic object upon your arm. If the balloon does not attract your arm hairs, humidity is too high.



Connect the circuit to its battery, and the LED will turn on. Comb your hair, then hold the comb near the Field Effect Transistor (FET) gate wire. The LED will go dark. This indicates that the comb has an excess of negative electric charge, and the FET responds to the electrostatic field surrounding the comb. It acts as a switch and turns off. Remove the comb and the LED brightens again. Wiggle the comb, and find at how great a distance the circuit still detects it. It's amazing how far an e-field extends around an electrified object. (But then, e-fields should extend to infinity, no?)

On a very low-humidity winter day the circuit will respond at a much greater distance. This happens because, when humidity is low, the combing of your hair then generates a much stronger separation of electric charge upon the comb's surface. Note that a metal comb will not work, since any separated electric charge immediately weakens by spreading to your hand and across your whole body. A plastic or hard rubber comb works well because rubber is an insulator and the imbalanced charges can't leak off the comb.

Try simply TOUCHING a plastic pen briefly to hair. The FET will detect even this tiny negative net-charge on the pen. The sensor will usually not indicate the equal positive that appears on your hair, since hair is made conductive by humidity, and the positive net-charge leaks to your head. The polarity of the surface electric charge on the comb or plastic pen is negative. The rule for this FET is, negative electric charge turns the switch (and the LED) off.


This FET sensor is not an ideal educational device because it responds differently to positive than to negative. Create some positive net-charge by affixing a small tuft of hair or wool to the end of a plastic object (pen or ruler), then rub the hair upon another plastic object. (If we electrify some hair, we can avoid leakage losses by not touching it with fingers or other grounded object.) Bring the positively-electrified hair near the FET. Note that the LED becomes brighter, but when the hair is removed, the LED goes dark and stays that way. Bring the hair close by again, and the LED lights up again. Rules for this FET:
  • negative objects turn the LED off, it lights again when removed.
  • positive objects make the LED bright, then dark when removed.
Turn the LED back on by simultaneously touching fingers to the "Gate" wire and to some other part of the circuit. Or, touch a plastic pen to some hair, then wave it near the sensor, and the LED will light up. Remember this trick when doing other demonstrations. (Note: professional electrometers do not suffer from this "reset" effect, but professional electrometers cost several hundred dollars at the very least!)

The MPF-102 is an "N-channel" transistor, and is turned off when the movable negative electrons in the transistor body are pushed out of the silicon, changing it to an insulator. You can also buy "P-channel" transistors which work backwards: their silicon is full of movable positive charges called "holes," and they are turned off by a positive charge on the gate. Try buying a few 2N5460 transistors from the usual suppliers ( Jameco , Mouser, Digikey )


Mount a tuft of hair on a plastic rod, verify that it is completely discharged and does not affect the FET. Take a second plastic rod (or plastic pen!) and verify that it is also completely neutral. (Fondle the whole pen with slightly damp hands if not.) Now hold the plastic handle and touch the hair-tuft to the tip of the pen, separate them, then hold them up to the sensor one at a time. You'll discover that the end of the plastic pen is now negative and turns the LED momentarily off. The hair tuft is positive and turns the LED on, then off.

Contact between the hair and the plastic caused some assymetrical sharing of the equal positive and negative "electricity" within them. When they separated, some negative electric charges stayed with the plastic, leaving it with more negatives than positive (net negative charge.) At the same time, the hair was left with fewer negatives than positives, for a net positive charge. Atoms were torn apart, "ionized", and pairs of electrons and protons were yanked apart and separated to vast distances. Note: "static electricity" is not caused by friction, it is caused by contact between dissimilar materials, followed by separation. We could say that it's caused by "peeling".


The "peeling" effect can be demonstrated with a roll of plastic adhesive tape. Peel a few inches of tape off the roll and hold it near the circuit. The LED will show that the tape is strongly electrified. Now use the sensor to test the tape dispenser. You will discover that the roll of tape has an opposite polarity compared to the strip of tape. This illustrates that "static" electrification does not require friction, it only requires intimate large-area contact between dissimilar materials.

Matter is made of positive and negative electric charge, and the peeling of tape can separate the electric charges that were already there in the matter. Because the plastic backing of the tape is a different material than the adhesive, when they touch together there is assymetric bonding and electron-sharing. This leads to separation of opposite charge when we peel tape from its roll. Also, try taking two strips of tape, stick them back to front (fold little tabs so you can separate them again,) pat them down with moist hands to discharge them, then peel them apart. Hold each near the sensor. One strip indicates strongly positive, the other is equally negative. The strips will attract each other. Try other demonstrations from Sticky Electrostatics, using the Charge Detector to show polarity of various parts of the tape.

[NOTE: people have found that "Scotch" brand tape doesn't work as well for the above activity. It contains some chemicals that prevent electrification. Use some other, inexpensive brand of tape instead.]


If you build a tiny compact version of the FET circuit (solder it to a torn-open battery connector), you can try the following trick. Hold the circuit in your hand, make sure the LED is lit, stand on a rug, then jump up and down. The LED will flash on and off. Walk around, and the same thing happens. As your shoe soles make contact with the rug and then peel away from it, your entire body becomes electrified. This makes the sensor respond. ANd when jumping, if you place your shoes back onto the oppositely electrified footprints, you cancel out the net electric charge and the sensor indicates another polarity change. Scuff your shoes, stomp up and down, jump around, and the sensor will flash wildly. Demonstrate to onlookers that the sensor does not respond when you shake it up and down, but it does respond when you jump. On a dry day, you can control the sensor with the tiniest motion: scuff one shoe, then lift the toe to turn the sensor on and off. Say "on", "off" while moving your toe, and you have a "voice control" magic trick. Let some poor fool examine the sensor, yell at it, etc. It will only respond to your voice! (grin!)


The circuit amplifies tiny voltages, and we can change it's "gain." Obtain a small capacitor with a value below 100 picofarads. Any value will do. Connect it between the FET's gate lead and one other FET lead (doesn't matter which one.) This greatly reduces the sensitivity of the device. In situations where the sensor is TOO sensitive, this can make a big difference. Capacitors larger than 100pF can be used, but they REALLY wipe out the sensitivity. The large the value, the smaller the sensitivity. The capacitor does this because it forms part of a circuit called a "Capacitive voltage divider," a sort of loudness control for invisible voltage fields.

Next, make the circuit MORE sensitive. Obtain an alligator clip-lead, and connect it to the Gate lead of the FET. Let it hang loose without touching anything. You'll find that this has vastly increased the sensitivity of your FET circuit. It does this by increasing the capacitance between the FET gate and the source of the voltage signal. On a dry day it will respond to hair-combing from 20ft away. If a TV screen is present, the sensor will act weird (especially when people walk between the screen and the sensor.) The clip lead acts as an extra antenna, and the longer it is, the more sensitive the FET circuit becomes.


Electrify a plastic object, place it on an insulating support, place the FET sensor near it, then make sure the LED is turned on. If you now wave your hand near the object or the sensor, the LED will respond. Your hand causes the e-field around the object to distort and change. Even though your hand is not electrified, the FET responds. You've created a sort of "DC Radar" system which sends out a signal and then responds when nearby objects "reflect" the signal. Some types of industrial sensors ("proximity" or "capacitive" sensors) use this effect. Some burglar alarms do as well.


See at what distance your FET electrometer can sense the e-field from an operating tabletop VandeGraaff electrostatic generator. Suddenly discharge the generator by using a grounded sphere electrode, and watch the distant FET respond. You are actually sending out radio waves with nearly zero frequency when you do this. The FET does not actually respond instantly, there is a speed-of-light delay (about one nanosecond per foot of distance.) It takes a short while for the wave of vanishing e-field to reach the sensor. Radio waves are simply propagating changes in electric fields, so your VDG machine and FET sensor constitute a simple radio transmitter and receiver.


The FET circuit is so sensitive that it will detect the energy stored on a tiny homemade capacitor. Build a simple capacitor out of aluminum foil, styrofoam (from a coffee cup), and wires. Store energy in the capacitor by briefly connecting it to a 9V battery. Now touch one capacitor wire to the negative battery terminal of the FET circuit, and touch the other capacitor wire to the Gate terminal (avoid touching the wires with fingers, this will discharge the capacitor.) The LED will indicate the stored energy. Use the 9V battery to reverse the polarity of the capacitor, then test it again with the FET and note that the polarity is indeed backwards. Note: don't use paper for your capacitor dielectric, paper becomes slightly conductive when humidity gets high, and your stored energy will mysteriously vanish because the paper offers a leakage path so the separated electric charges can recombine. Another note: this experiment demonstrates that "static electricity" and battery circuits are the same. The FET detects the potential difference created by the 9V battery, just as it detects the much larger potentials in the space around electrified objects. It is not too far wrong to say that "static electricity" is simply "voltage." Everyday circuits are driven by the "static electricity" produced by their low voltage power supplies.


After you use this FET device for awhile, you'll get the idea that it has just a single antenna terminal. However, like all voltmeters, it actually has two. The rest of the circuit acts as the other terminal. To demonstrate this, build a miniature version of the detector circuit onto the top of a 9V battery. If you hold the battery as usual, the Gate does act as the antenna, and negative objects make the LED go dark. Now carefully grasp the Gate wire between fingers and lift the whole device into the air. Avoid touching the battery. If you now hold a negatively electrified object near the battery, the LED will get brighter instead of dimmer. Polarity of operation has been reversed. If you lay the whole unit down upon an insulating surface and approach it with electrified objects, you'll find that the FET gate wire responds with one polarity, while the battery and the rest of the circuit responds with the other. Try connecting the gate wire to earth ground, then suspend the rest of circuit with an insulating handle. If you hold up objects having various polarities, you'll find that polarity of operation is opposite that of the gate wire.


All over the earth, thunderstorms are transporting negative electric charge downwards and positive charge upwards. As a result, the earth is electrified negatively everywhere, while the sky is positive. (Actually, it's the conductive ionosphere which is positive.) The FET sensor can detect this. Take it outdoors, away from trees or buildings. Hold it high in the air, then lower it to the ground while watching the LED. (Maybe get a tall adult to do this.) The LED will get darker when the device is lowered, and get brighter when it is raised up. The earth is negative! Maybe hang a cliplead antenna on the sensor wire to improve sensitivity. (This polarity reverses when there is a thunderstorm directly overhead, but I wouldn't suggest standing out in the open when there is a chance that lightning may strike!)


This one is for science teachers and advanced experimenters only. Voltages above 60V are a shock hazard! If you do not know how to safely work with dangerous high voltage, then don't perform this experiment.

Get ten 9V batteries. (Old batteries are fine, as long as they still put out 8V or more.) Form them into a chain like so: place five batteries side by side on the table, so the connectors all are aligned the same way. Then link them together by plugging the other five batteries upside down into the first batteries. This creates a connected block of batteries. It's a ninety-volt battery. Now wave the antenna of the FET circuit around this battery chain. DON'T LET THE ANTENNA TOUCH ANY OF THE BATTERIES OR THEIR CONNECTORS! You'll find that the negative end of the battery chain will make the LED go dark.

See what's happening? Batteries can create "static electricity" effects. But it only happens at high voltage. The voltage of a single 9V battery does not affect the FET sensor, because the e-field of a 9V battery is a bit too weak. But a 90V battery creates an e-field ten times stronger!


Here are a couple of things to try out. I haven't tested them, I don't know how well they work. You be first!

Electrify a large plastic object while no one sees, then have a group of people with FET-based charge-detectors try to find which object in the room has the imbalanced electric charge.

Have everyone build FET electrometers. Line them all up in a row, electrify a plastic object, then sweep the object back and forth. You'll be able to "see" the electrostatic field that surrounds the object. Hold your hand near the row of detectors while standing on a rug. Jump up and down and see what happens.

Use a piece of cloth to create a small electrified spot on a plastic book cover. Use the FET device to find the spot. Draw an electrified shape using the cloth as a paintbrush, then see if you can use the sensor to figure out what the shape is.

Build many FETs and LEDs in a row on a wooden stick. Connect them all to one battery. Place a negatively electrified object on a table in a dimly lit room, then sweep the FET-stick rapidly past the object. Go back and forth really fast, and you should see a row of red lines caused by the moving LEDs. In the middle of the red lines will be a black splotch caused by the electrostatic field surrounding the negative object! Repeat this test, but this time use a bit of cloth to write the letter "A" on a plastic book cover in invisible, negative net-charge. Can you see the "A" when you sweep the stick back and forth? Mount your row of LEDs on some sort of motorized propeller, and you'll have an automated "charge detector disk."


The circuit is an electronic version of an Electroscope. Electroscopes are simple science instruments for measuring high voltage. Electroscopes have been in use for hundreds of years.

This FET charge-detector circuit is based on a much earlier circuit called "electronic electrometer" made with a vacuum tube. As a kid I found the schematic in an old paperback book on ham radio projects from Pop. Electronics magazine. It used a 6J7 tube and an NE2 bulb and 100K resistor connected to the plate terminal. I blew away my allowance for weeks to buy that tube (plus a 6.3V transformer, plus a fancy bakelite box.) It used 120VAC line voltage connected to the cathode and the LED (the tube then acts as a rectifier.) The 6J7 tube has a terminal on the top which connects to the tube's Grid terminal (a "grid cap," rather than the more usual plate cap.) My 'antenna' came from a coffee can run through the can-opener, plus the plastic can lid to protect the sharp metal edge. When a negatively electrified plastic pen was waved near the grid, the glowing NE2 would turn off. On winter days the sensitivity was quite amazing.

Other modern devices also respond to nearby electrified objects. When FETs first were sold, I bought one and used an ohm meter to measure across source/drain. Sure enough, when an electrified object was waved near the unconnected grid wire, the ohmmeter reading went crazy. Also, if you have an FET-type opamp chip (TL072, etc.), and you leave the input floating, or if you have CMOS logic chips with the inputs floating, they will sometimes act crazy when you wave your hand around them. Unless the humidity is very high, your body usually has enough DC charge to turn them on or off.

I tested several common FETs to find a sensitive one, and discovered that MPF102 was much more sensitive than the original vacuum tube I had as a kid. With a couple feet of gate terminal wire, I could turn it on and off by waving an electrified plastic comb back and forth from over ten feet away. (With longer antennas it started picking up 60Hz hum, and was overloaded.) Later at the Museum of Science in Boston I designed an exhibit, an array of many hundreds of these things, each with a small steel screw as the antenna. See "Aura Tester". Also see a bit more about the circuit.


A complete description of this device requires delving into the physics of solid state electronics. Instead, here is a quick description based on the fluid analogy for electric charge.

Metals act as conductors NOT because charge can pass through them. Instead, they are conductors because they contain charge which can move. Think of a metal wire as being like a hose that's aways full of water. And remember, vacuum is an insulator, even though it presents no barrier to charges. But vacuum contains no charges which can move.

The "sea of charge" in a metal is not very compressible. To squeeze (or remove) even a tiny bit of it would take a huge amount of energy. In metals, the "electricity fluid" is dense like water, since each atom contributes one electron to an "electron sea." The number of atoms is enormous, so the amount of mobile charge is enormous too. Inside metals, , atoms' outermost electrons don't stick to single atoms but instead orbit all throughout the material. (So, a metal object is like a tank of "fluid electricity," and a metal wire is like a full pipe.) If we could remove all the movable electrons from a metal, that metal would become an insulator. Unfortunately, removal of electrons from even the thinnest metal wire requires gazillions of Newtons of electrostatic force, and develops gazillions of volts of potential difference. ("Gazillions" means some huge number with waaaay too many zeros!). Metals are highly conductive, and we can't easily change that.

This is where silicon comes in. While a metal's electron-stuff acts like a dense fluid, in silicon the mobile charges act like a sparse and compressible gas. In silicon, only very few atoms contribute a mobile electron to the "charge sea." In fact, the silicon doesn't really contribute electrons at all, and ultra-pure silicon is an insulator. Instead, only the tiny bits of impurity atoms in the silicon will contribute movable electrons. If we only put a tiny, tiny fraction of a percent of impurities into the silicon mix, then the resulting material's movable electron-stuff becomes much more compressible than the "electron sea" within a metal. It acts almost like a gas, not an incompressible fluid. This reduces the required voltage and force (by a gazillion times!) reducing the force that's needed to push the movable charges out of the silicon. The electron-sea of a metal is not very compressible. The electron-gas within silicon is very compressible.

So what? Well, if we can push the "electron sea" out of a conductor, we can change it into an insulator. It would be like pinching a hose shut, so no liquid could flow. I would be like turning off a switch, but almost no work is required to do this. Just apply an electrical "push" in the form of electrostatic repulsion, then the silicon becomes insulating, so large currents can be switched on and off.

The Field Effect Transistor is basically a tiny wafer of silicon with its edges connected to the "Source" and "Drain" wires, and the "Gate" lead connected to a metal plate layed upon the surface of the silicon wafer. When the gate lead is electrified negative, it repels the electron-gas out of the silicon and converts it into an insulator. The silicon wafer acts like an electric switch that is turned off by pure voltage. If we picture the silicon as being like a rubber hose full of water, then the gate applies a sideways force which pinches the hose closed. Placing a negative net-charge on the gate wire causes the "switch" to turn off and the LED to go dark. Merely holding a negatively electrified object near the Gate lead will apply a force to the electrons in that little Gate wire, which pushes them into the metal plate, which repels away the electrons in the silicon, which pinches closed the conductive path.

Interesting part: it really takes no energy to turn off the FET. It does take electrostatic force, but force is not energy! And so, even a very distant object with a feeble net-charge can affect the FET and control the much larger energy being directed to the LED.

The FET is not really turned off by negative net-charge. That is an overly simplified description. It is really turned off by a DIFFERENCE in the net-charge between the silicon and of the metal plate. You can either electrify the metal plate negatively, or electrify the silicon positively (which also electrifies the battery, LED, and circuit wires.) Both will turn the FET off by pushing (or pulling) the electrons out of the silicon. Think of the rubber hose again: either you can squeeze it shut with fingers, or you can lower the pressure of the whole water circuit, and the hose will be collapsed by "suction" (by air pressure, actually.)

What are FET transistors good for? Well, most modern computers are constructed almost entirely from FETs. The megabytes of memory are formed from little grids of millions of microscopic FETs, each with a net-charge stored on its gate lead signifying a zero or a one. The processor chips are built of logic switches with Gate voltage as their input, and on/off switching as their output. Other things: super-FETs can be built which actually contain many thousands of small FET transistors all hooked in parallel. These VFETs or HEXFETS are often used as the main transistors of large audio amplifiers. A tiny vibrating voltage on their gate lead can route many amperes of charge-flow at sound-frequency, through the loudspeakers, and a handful of FET wafers the size of your fingernail control the audio power for a whole rock concert.



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