2. Spark Length
To measure high voltage, attach two large and polished brass balls (2"
dia. or larger) to an insulating plate so there is a 1/2 millimeter
gap between them. You can verify the 2,800-volt breakdown voltage of this
spark gap by using a high-voltage DC power supply to produce sparks
between the balls. Now disconnect the power supply, ground one brass ball,
hold your finger against the other one, and start madly scuffing your
shoes on the rug. Sparks leap across the gap. Your body charges up to 3
kilovolts, and causes a spark-gap breakdown, just like the power supply
did. (I've done variations on this measurement technique many times,
since it makes an expensive electrometer unnecessary.) Sometimes, when
humidity is extremely low and the rug is totally dry, you can widen the
gap spacing by quite a bit, which implies that human body voltage exceeds
2,800 volts by quite a bit. Hint: rather than using large and expensive
brass spheres, use two stainless steel mixing bowls. Mount them on some
sort of plastic insulators so the round bottoms face each other across the
tiny gap.
3. Doorknob spark, relative pain
Use an adjustable, calibrated High Voltage DC power
supply to charge your body to various voltages (
EXTREME DANGER! Limit the
current to below a few hundred uA by using a series resistor chain. If
you don't know how to use DC high-volt power supplies safely, then don't
mess with them. IF YOU DO THIS WRONG, IT CAN KILL YOU.) Use the
power
supply to charge yourself to 3KV, 5KV, 7KV, and touch a grounded knob each
time. No electrometer is needed, yet you've just verified the length,
sound, and pain-level of the fingertip spark which appears when your body
had been forced to take on certain high voltages. This procedure is
a great way to learn the types of sparks produced by various
voltages on your body, so the next time you get zapped by a car-door, you
can say "YOW!, the ouchiness-factor of that spark indicates a human body
voltage on the order of seven kilovolts." :)
4. Hand-waving AC field magnitude
Crudely measure your body-voltage by using an
oscilloscope to compare it to a high-voltage power supply. First, connect
an oscilloscope's input to a metal plate. Scuff on a carpet (during a
low-humidity day), wave your hand near the metal plate, and see how much
the trace on the oscilloscope is deflected. Adjust the scope's vertical
gain to give a fairly large deflection during your hand-waving. (Don't
TOUCH the plate while your body is charged, or you might blow out the
input amplifier on the scope!)
Next, use a DC high-voltage power supply with a large current-limiting
series resistor to charge your body to 5,000 volts. (
EXTREME DANGER! You
MUST limit the current to below a few hundred microamps by using a series
resistor chain. If you don't know how to handle high-volt DC power
supplies safely, then don't mess with them. IF YOU DO THIS WRONG, IT CAN
KILL YOU.) Wave your charged hand near the metal plate while
seeing how
far the oscilloscope trace deflects. Adjust the HV supply voltage until
the deflection is about the same as when your body was charged by the
rug-scuffing. Read the power-supply voltage setting, and you will
know
the approximate body-voltage produced by rug-scuffing.
5. Crude and simple "field mill"
A more precise version of no. 4 above... Build a crude
"field-mill" e-field sensor. TO do this, first use a small DC motor
to whirl a grounded
wire, then place an oscilloscope probe behind the whirling wire so it is
alternately shielded and unshielded, mount the entire assembly an inch or
so from a large, electrically floating brass ball, then observe the scope
trace. The observed AC voltage will be proportional to any DC voltage on
the isolated brass ball with respect to ground. Apply a known kilovoltage
to the brass ball in order to calibrate it against the AC reading on the
scope (for example, 1,000 volts applied to the brass ball will produce a
certain AC voltage reading on the scope, and any other voltage applied to
the brass ball will be proportional.) Now go scuff on a rug while keeping
one finger on the brass ball, and see what voltage is detected by the
system. (No oscilloscope? Try placing a small metal disk behind the
whirling wire, then connect a digital voltmeter to the plate and to
ground,
then set the meter to a sensitive scale on AC volts. Calibrate the
voltage reading on
the meter against a known DC high voltage applied to the brass ball.)
To measure REALLY high voltages (such as those produced by a VandeGraaff
machine), you can use the above technique, but use the VDG sphere itself
instead of the "brass ball", and place the field-mill and the oscilloscope
several feet away from the VDG sphere. Calibrate it as before. If 1KV
applied artificially to the VDG sphere produces a certain waveform
voltage, then 100KV
will produce exactly 100 times higher AC voltage.
6. Electrometer Array
Build 300 crude electrometers which drive individual LEDs. Use them to
build a "visible e-field detector panel." When charged objects approach
the panel, the glowing field of LEDs darkens in a pattern around the
object. Scuff on the rug, hold a hand up, and observe the darkened field
around your hand. What body voltage does this imply? To find out, go
grab the old 7KV supply, hold the live terminal, then wave your hand
around the sensor panel. Whoa! The darkened field is larger than before.
Decide that the rug-scuffing body-voltage must have been maybe half of the
body
voltage created by the 7KV supply, maybe 3,500 volts.
OTHER WAYS TO VERIFY THAT "STATIC ELECTRICITY" INVOLVES HIGH VOLTAGE
Read books which say that common "static electric" sparks first appear
when
the voltage on your body rises above 500VDC. Use a HV DC power supply to
test this, and find that their estimate is too low, that sparks cannot be
seen at all until 750V, and they are very hard to notice until the voltage
on your body is above 1KV.
Calculate what happens when a charged balloon is
lifted from your arm. Obtain a value of 100KV. Sounds sensible.
Ordinarily
a VandeGraaff Generator would be needed to make arm-hair stand up so
fiercely.
Read research papers from people who measure such things. Here's one from
J. Chubb Inc:
The Control of Body Voltage Getting Out of a Car
Their measurements for different clothing and various car-seats give
impressively high voltages, and this occurred at humidity levels
above 50%. The voltages should be MUCH higher at, say 5% R.H.!
- Nylon clothes: 21,000 volts (Yowch!)
- Wool clothes: 9,000 volts
- Cotton clothes: 7,000 volts
Here's a suggestion taken from the PHYS-L discussion group:
Touch the electrode of a foil-leaf electroscope, and simultaneously
scuff on the carpet. Observe the deflection of the foils. Now connect
the
electroscope terminal to an adjustable HV DC power supply with the
other HV supply terminal connected to ground, and adjust the voltage to
duplicate the foil deflection from before. Read the voltage. The
power-supply
voltage is the same as your rug-scuffing body-voltage was.
RUBBED-BALLOON VOLTAGE CALCULATION
I rub a balloon upon my arm hair. If I know the attraction force and the
capacitance between those flat, plate-like regions of opposite charge,
then I can calculate the voltage. If the attraction force is 0.1Nt (like
a 10gram weight) and if it is independent of plate-separation (because the
plates are closely spaced,) and if the spacing of the "capacitor plates"
is initially 1mm (0.001meter), then it took an amount of energy equalling
(Force*distance) to pull the attractive plates apart to 1mm, and the
stored energy is:
Work = force * distance
.1Nt * .001meter = 1e-4 Joules. For the given attractive force between
the plates, we see that 100 microjoules of electrical energy is stored by
this capacitor.
OK so far? Now, what is the capacitance of two capacitor plates spaced
1mm apart and having the size of that typical contact area between the
balloon and my forearm? Let's say the area is 4cm by 15cm, or .04*.15 =
.006 square meters. The equation for calculating the capacitance of
parallel plate capacitors (plates spaced very close) is
C = k * A/D
Capacitance = k*area / distance between plates, where the dielectric
constant of air is k=8.9e-12 and the lengths are in meters, so the
capacitance of the balloon/arm capacitor at a 1mm gap is 53pf.
An actual 4cm x 15cm foil-plate capacitor with a paper-stack dielectric
measures 95pf on my capacitor meter, which is in the ballpark. We should
expect it to be higher than our 53pF above, since it has a paper
dielectric, not air.
The energy stored was 100 microjoules, so the voltage can be had from the
equation for stored energy in capacitors:
U = 0.5 * C * V^2
Energy equals one half times capacitance times voltage squared, or
Voltage=sqrt(2*U/C) (U is the stored energy.) Plugging in 100 microjoules
and 53 pf I get an answer of 1900 volts. At 1mm spacing, the voltage is
already almost 2,000 volts!
I also get a total charge of each imbalanced region which calculates to be
about 0.1 microcoulomb:
U = 0.5 * Q^2 / C
U = F * d
Q = sqrt(2*C*F*d)
Force * distance = 1/2Q^2/C, or Q = sqrt(2CFd) = 1e-7coulombs. Capacitor
voltage is always V = Q/C, and capacitance varies inversely with
plate-spacing, therefor voltage varies directly with plate spacing.
Double the plate spacing of charged, insulated plates, and we double the
voltage.
V = (1e-7)*D/(.006)/(8.9e-12)
plate
spacing V(capacitor)
1mm 1920v
5mm 9600v
1cm 19200v
5cm 95800v
WHOA! 100,000 volts at a couple of inches spacing?!! However, this is
reasonable, since it normally takes a VandeGraaff Generator to make
arm-hair stand up so painfully rigid. In the gap between the balloon and
my arm-hair, we have electric field strength which is easily the same as
the field strength at the surface of the sphere of a VDG machine. Also,
the capacitor equation stops working correctly as we exceed about 1cm,
when the plate spacing becomes large in comparison to the shortest side
of each plate. Maybe the voltage at 5cm is really only 50,000
volts. Only!!!!!!!
The capacitor voltage varies as the square-root of the attraction force,
so what would happen if this force was smaller? If the attraction
between my arm and the balloon was only 0.01Nt (1 gram weight), then the
voltage would start at 606V at 1mm, and go up to 6060V at 1cm. Not as
huge, but still pretty impressive.
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