However, if we consider
the capacitor as a whole, no electrons have been put into the capacitor.
None have been removed. The same number of electrons are in a "charged"
capacitor as in a capacitor which has been totally "discharged." Yes, a
certain amount of charge has been forced to flow momentarily during "charging," and a rising potential difference
has appeared. But the current is directed through the capacitor, and the
incoming electrons force other electrons to leave at the same time. Every
bit of charge that's injected into one terminal must be forced out of the
other terminal at the same time. The amount of charge inside the capacitor
never changes. The net charge on each plate is cancelled by the opposite
charge on the other plate. Capacitors are never "charged" with electric
Think about this:
When "charging" a capacitor, a momentary current causes the voltage to rise. Volts times electron-flow equals energy-flow ( V x I = P). Therefore during a momentary current through a capacitor, there is a joules-per-second transfer of energy from the power supply into the capacitor.
Similar trouble is caused when we say that we "charge" a battery. We
charge a battery with some energy in the form of stored chemical fuel, but
we pump electric charge through the battery and none of it builds up
inside. Fuel-chemicals build up inside. Charge doesn't.
It's all terribly confusing. What are students to think if we
tell them that "charging a battery" does not store any charge,
yet charge must flow through the battery if we want to charge it! Ugh.
The word "charge" has far too many meanings. In science this is always a
Very Bad Thing.
Another, less misleading situation is similar: think of the word "charge"
as applied to gunpowder. A charge is placed in an old cannon, followed by
a cannonball. It would be silly to assume that, because we've "charged"
the cannon, the cannon now has an electrical charge. But whenever we
state that we've "charged" a capacitor, we do assume that an electrical
charge has been stored inside. This is just as silly as mistaking
gunpowder for electrostatic charges. Charging a capacitor is like
charging a cannon; in both situations we are inserting energy, not
Here's yet another way to visualize it. Whenever we "charge" a capacitor,
the path for current is through the capacitor and back out again. The
extra electrons on one plate force electrons to leave the other plate, and
vice versa. Visualize a capacitor as being like a belt-driven wind-up
motor. If we shove the rubber belt along, the spring-motor inside the
capacitor winds up. If next we let the rubber belt go free, the wound-up
spring inside the motor drives the belt in the other direction, and the
spring becomes "discharged." But no quantity of "belt" is stored inside
this motor. The belt flows through it, and we wouldn't want to label
this motor as a "machine which accumulates rubber." Yet this is exactly
what we say whenever we state that a capacitor "stores charge."
One more try. Capacitors store charge in the same way that resistors
store charge, and inductors store charge. Inductors are full of mobile
electrons, inductors are devices for storing charge!!!! Not. A capacitor
is not a bucket for electrons. Instead it greatly resembles a length of
wire. But it's wire which, whenever you run a current along it, the total
charge inside the wire stays constant, but a voltage (and a charge
imbalance) appears at the two ends.
My favorite capacitor analogy is a heavy hollow iron sphere which is
completely full of water and is divided in half with a flexible rubber
plate through its middle. Hoses are connected to the two halves of the
sphere, where they act as connecting wires. The rubber plate is an
analogy for the dielectric. The two regions of water symbolize the
Imagine that the rubber plate is flat and undistorted at the start. If I
connect a pump to the two hoses and turn it on for a moment, the pump will
pull water from one half of the iron sphere and simultaneously force it
into the other. This will bend the rubber divider plate more and more.
The more the plate bends, the higher the back-pressure the plate exerts,
and finally the pressure-diff will grow strong enough that the pump will
stall. Next I seal off the hose connections and remove the pump. I now
have created a "charged" hydraulic capacitor.
Now think: in this analogy, water corresponds to electric charge. How
much water have I put into my iron sphere? None! The sphere started out
full, and for every bit of water that I took out of one side, I put an
equal amount into the other at the same time. Same as when running a
current through a conductor. When the pump pushed water into one side,
this extra water also forced some water out of the other side.
No water passed through the rubber, instead there was some rubber-current
in the divide. Even so, essentially I drove a water
current through my hydraulic capacitor, and this current pushed on the
rubber plate and bent it sideways. Where is the energy stored? Not
in the water, but in the potential energy of the stretched rubber plate.
The rubber plate is an analogy to the electrostatic field in the
dielectric of a real capacitor.
It would be misleading to say "this iron sphere is a device for
accumulating water", or "this sphere can be charged with water, and the
stored water can be retrieved during discharge." Both statements are
wrong. No water was injected into the sphere while it was being
"charged." (And when I wind up an old watch, am I "storing steel"
inside, putting more iron into its spring? Lol.
Imagine that I now connect a single length of pre-filled hose between the
two halves of the capacitor. As soon as the last connection is complete,
the forces created by the bent rubber plate will drive a sudden immense
spurt of water through this already-full hose. Water from one side will
be pushed into the other side, and the rubber plate will relax. I've
discharged my hydraulic capacitor. How much water has been removed from
the sphere? None! A momentary current has flowed through the sphere
device, and the rubber plate is back to the middle again, and the water
has become a bit warm through friction against the surfaces of the hose.
The stored energy has been "discharged," but no water has escaped. The
hydraulic capacitor has lost its energy, but still contains the same
amount of water.
I never really understood capacitors until I started trying to construct
proper water-analogies for them. I then discovered that my electronics
and physics classes had sent me down a dead-end path with their garbage
about "capacitors store electric charge." Since my discovery, I've gained
significantly more expertise in circuit design, which leads me to a sad
thought. Maybe the more skilled of electrical engineers and scientists
gain their extreme expertise not through classroom learning.
gain expertise in spite of our K-12 classroom learning. Maybe the experts
experts only because they have fought free of the wrong parts of grade
school science, while the rest of us are still living under the yoke of the many
electricity misconceptions we were taught in early grades.
[Hey^2!!! I just found that Oliver Lodge was building mechanical analogies for Maxwell's descriptions of EM fields and circuits... and for an 1880 lecture he built a capacitor hydraulic analogy consisting of a water-filled globe containing a smaller water-filled balloon.]
Extra notes:Capacitors store just as much charge as coils do! In both devices the total amount of charge stays constant. Both capacitors and inductors are components for storing electromagnetic energy. They're two sides of the same EM phenomenon: a coil stores energy in a volume containing a magnetic field, while a capacitor does something similar with electric fields. Coils are "discharged" by interrupting a large current and collapsing the b-field, while capactors are discharged by shorting-out a large voltage and collapsing the e-field. Neither stores any "electricity" (unless by the word 'electricity' you mean magnetic field?) Of course you can place a coil atop an insulating platform, then use a VandeGraaff generator to give your coil a large net-charge! You can do the same with a big electrolytic capacitor too. :)
Bill Beaty here again. Two points: First, the heated topic about dielectric being an insulator, and currents being impossible between capacitor plates ...seems to be about VACUUM CAPACITORS, not capacitors in general. Modern capacitors are quite different, and inside their dielectric is a large electron current. They aren't vacuum capacitors. Relative Permittivity can be seen as a ratio between the small Maxwell's displacement current in the dielectric, versus the larger dielectric polarization current (electron flow.) The dielectric constant in modern ceramic capacitors is above 2,000, so the vast majority of the current is from moving electrons in the ferroelectric ceramic. That's a genuine charge flow. The Maxwell displacement current is insignificant: well below 1%. Second: it might help to ask whether, down at the micro level within any conductor, is there any current BETWEEN the charge carriers? If there is, then there's certainly a current between the carrier-filled plates of a vacuum capacitor. Or said differently: if we have a current-sensor, and a charged particle approaches and passes it, does our sensor indicate an extremely brief pulse, where the pulse-width is associated with the diameter of the charged particle? Or instead does our sensor see each moving particle as being large and "fuzzy," where the measured current is in the fields surrounding each particle, and the current extends forwards and back from the particle location? A clamp-on inductive sensor (Rogowski coil) doesn't detect charges or their motions, instead it detects changing flux-linkage. A clamp-on sensor would report that a charged particle is indeed large and fuzzy, and the current exists in the empty spaces between the flowing charges. Current is not just on the particles' surfaces where the charge actually resides. So, a clamp-on sensor would 'see' currents in the capacitor's empty gap. Two points? Third point (I lied!), suppose we construct a capacitor where the dielectric takes the form of a long rod: much thicker than the diameter of the capacitor plates. Use a long narrow lead-zirconate- titanate PZT rod with capacitor plates attached to its circular ends. Now apply some 27MHz amperes. Do you insist that the current within the rod is zero? Really? It's not. Suppose we obtain a coil-shaped spiral rod of PZT. A "ferroelectric coil." If we apply some RF amperes through this spiralled capacitor, we'll certainly detect a strong magnetic field surrounding the device. If the current is supposedly zero within all capacitor dielectrics as some people angrily insist, how can we explain this?